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`        A sledge moving over a smooth horizontal surface of ice at a velocity v2 drives out on a horizontal road and comes to a halt. The sledge has a length l, mass m and friction between runners and road is mhu`
3 months ago

Saurabh Koranglekar
3162 Points
```							Dear studentPlease tell what is to be done in questionRegards
```
3 months ago
Khimraj
3008 Points
```							Assume that the spring compression is x .Here , the Initial kinetic energy of the block K.E = 1/2 mv²When the spring is compressed at it maximum range at that point the Kinetic energy will be changed to potential energy .P.E = 1/2 mx²Now from the law of conservation of energy .we get1/2 mv² = 1/2 kx²mv² = kx²v² = kx²/mx² = (v² × m) /kThe maximum compression x, is ⇒Now for the second case , we assume that there is no loss in the spring. So the kinetic energy is the same when spring comes to it's original position.But velocity is a vector quantity , so it will not be same as like original . Hope it Helps.
```
3 months ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions