0

Guest

Courses New

A sledge moving over a smooth horizontal surface of ice at a velocity v2 drives out on a horizontal road and comes to a halt. The sledge has a length l, mass m and friction between runners and road is mhu

A sledge moving over a smooth horizontal surface of ice at a velocity v2 drives out on a horizontal road and comes to a halt. The sledge has a length l, mass m and friction between runners and road is mhu

Grade:12

2 Answers

Saurabh Koranglekar
askIITians Faculty 10335 Points
4 years ago
Dear student

Please tell what is to be done in question

Regards
Khimraj
3007 Points
4 years ago
Assume that the spring compression is x .
Here , the Initial kinetic energy of the block 
K.E = 1/2 mv²
When the spring is compressed at it maximum range at that point the Kinetic energy will be changed to potential energy .
P.E = 1/2 mx²
Now from the law of conservation of energy .we get
1/2 mv² = 1/2 kx²
mv² = kx²
v² = kx²/m
x² = (v² × m) /k
The maximum compression x, is 
⇒Now for the second case , we assume that there is no loss in the spring. So the kinetic energy is the same when spring comes to it's original position.
But velocity is a vector quantity , so it will not be same as like original . 

Hope it Helps.

Think You Can Provide A Better Answer ?

Other Related Questions on Mechanics

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More