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Grade: 11

                        

A simple U-tube contains mercury. When 11.2 cm of water is poured into the right ann, how high does the mercury rise in the left arm from its initial level ?

5 years ago

Answers : (2)

Aditi Chauhan
askIITians Faculty
396 Points
							236-1888_1.PNG
236-2301_1.PNG
5 years ago
ankit singh
askIITians Faculty
596 Points
							
When water is added to one side of the U tube, the rise in mercury level of the other side of the U tube will be depend on the density of water and mercury.
The height of water added in one arm = 13.6cm, we have to calculate the corresponding rise in level in the other arm
The pressure difference tn the two arms will be equal
So, the pressure difference in water column = the pressure difference in the other arm or mercury
                     i.e. hHg d g  = hW d g
                          hHg    = hW×density of water × g ÷ density of mercury × g
                                  = 13.6cm × 1000kg/m3 × g ÷ 13.6 × 1000kg/m3 × g
                                  = 1cm
i.e. When 13.6cm water is added to one arm of the U tube, only a height of 1cm will be the rise in mercury level in the other arm
3 months ago
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