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A simple pendulum of length 1 meter has a Bob of 200 gram. It is displaced through 60 degree from the vertical and then released . It's kinetic energy , when it passed through the mean position is?

A simple pendulum of length 1 meter has a Bob of 200 gram. It is displaced through 60 degree from the vertical and then released . It's kinetic energy , when it passed through the mean position is?
 
 

Grade:11

1 Answers

Arun
25750 Points
5 years ago
Dear Kashish
 

we know the simple kinetic energy formula,

K.E=1/2*m*v² ————-(1)

we know m = 200g, but v = ??

here’s where the pendulum sh*t kicks in,

v=√2gl/m (cos(θ)−cos(θo))

here, θ = angle made by the pendulum at mean position (here in question)

and,

θo = angle made by the pendulum at its highest (60)

and taking obvious things into play like m = 200gm, g = 9.8 m/sec^2, l = 1m,

we get v = 0.7 m/sec

Aaaand plugging it into (1)

we get …………,

K.E = 0.049 N.m

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