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A simple pendulum of length 1 meter has a Bob of 200 gram. It is displaced through 60 degree from the vertical and then released . It's kinetic energy , when it passed through the mean position is?
Dear Kashish we know the simple kinetic energy formula,K.E=1/2*m*v² ————-(1)we know m = 200g, but v = ??here’s where the pendulum sh*t kicks in,v=√2gl/m (cos(θ)−cos(θo))here, θ = angle made by the pendulum at mean position (here in question)and,θo = angle made by the pendulum at its highest (60)and taking obvious things into play like m = 200gm, g = 9.8 m/sec^2, l = 1m,we get v = 0.7 m/secAaaand plugging it into (1)we get …………,K.E = 0.049 N.m
we know the simple kinetic energy formula,
K.E=1/2*m*v² ————-(1)
we know m = 200g, but v = ??
here’s where the pendulum sh*t kicks in,
v=√2gl/m (cos(θ)−cos(θo))
here, θ = angle made by the pendulum at mean position (here in question)
and,
θo = angle made by the pendulum at its highest (60)
and taking obvious things into play like m = 200gm, g = 9.8 m/sec^2, l = 1m,
we get v = 0.7 m/sec
Aaaand plugging it into (1)
we get …………,
K.E = 0.049 N.m
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