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Grade 12th passGeneral Physics

A shot after leaving the gun at around passes over a wall horizontally . if the wall is 10 m high and 30 m away from the gun find the velocity of projection and direction of shot

sayali gavali

8 Years agoGrade 12th pass

1 Answer

Eshan

8 Years ago

Dear student,

Consider the motion in two coordinate axes, horizontal and vertical ones.

In the vertical direction,

$0^2-u_y^2=2(-10)(10)$
$\implies u_y=10\sqrt{2}m/s$

Time in which the particle crosse the wall= $\dfrac{u_y}{g}=\sqrt{2}s$
Hence the horizontal component of the velocity of projection is $u_x=\dfrac{30}{\sqrt{2}}m/s=15\sqrt{2}m/s$
Hence $tan\theta=\dfrac{u_y}{u_x}=\dfrac{2}{3}$

$\implies u=5\sqrt{26}m/s$

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