Grade 12th passMechanics

A ship of mass 3 × 107 kg initially at rest, is pulled by a force of 5 × 104 N through a distance of 3m. Assuming that the resistance due to water is negligible, the speed of the ship is
a) 1.5 m/sec.
b) 60 m/sec.
c)0.1 m/sec.
d) 5 m/sec.

satendra

12 Years agoGrade 12th pass

2 Answers

bharat bajaj

12 Years ago

A = F/m = 5 × 104/ 3x107

From newton third law

V^2 - u^2 = 2as

V^2 = 2 x 5 x 3 x 104/3x107

It comes out to be near 3 m/ sec

There is no such option. The answer is correct. Please check the values again

Thanks

Bharat Bajaj

Askiitians faculty

Nilesh

9 Years ago

F=ma

5*10⁴ = (3*10⁷) a

a = (5/3)*10^-3

Now, By newton’s third law of motion,

v² – u² =2as

v² – 0² = (2)*(5/3)*(10^-3)(3)

v² = 10^-2

v = 0.1 m/s

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A ship of mass 3 × 107 kg initially at rest, is pulled by a force of 5 × 104 N through a distance of 3m. Assuming that the resistance due to water is negligible, the speed of the ship isa) 1.5 m/sec.b) 60 m/sec.c)0.1 m/sec.d) 5 m/sec.

satendra

2 Answers

bharat bajaj

Nilesh

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A ship of mass 3 × 107 kg initially at rest, is pulled by a force of 5 × 104 N through a distance of 3m. Assuming that the resistance due to water is negligible, the speed of the ship is
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