A ship of mass 3×10^7 kg is at rest.By applying a force of 30×10^5 Newton it is displaced through a distance 25 m. Then the speed of ship after this displacement is

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Arun · Answer

Dear student a = F/m = (30×10 5 )/(3×10 7 ) = 0.1 m /sec^2 Speed attained by the ship, v = √2as = 2.236 m/s Regards Arun (askIITians forum expert)

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A ship of mass 3×10^7 kg is at rest.By applying a force of 30×10^5 Newton it is displaced through a distance 25 m. Then the speed of ship after this displacement is

A ship of mass 3×10^7 kg is at rest.By applying a force of 30×10^5 Newton it is displaced through a distance 25 m. Then the speed of ship after this displacement is

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