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A ship of mass 3×10^7 kg is at rest.By applying a force of 30×10^5 Newton it is displaced through a distance 25 m. Then the speed of ship after this displacement is

A ship of mass 3×10^7 kg is at rest.By applying a force of 30×10^5 Newton it is displaced through a distance 25 m. Then the speed of ship after this displacement is 

Grade:12th pass

1 Answers

Arun
25763 Points
3 years ago
Dear student
 
 a = F/m = (30×105)/(3×107 ) = 0.1 m /sec^2
Speed attained by the ship, v = √2as = 2.236 m/s
 
 
Regards
Arun (askIITians forum expert)

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