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Grade 12Mechanics

A satellite orbits around a planet whose mass increases with time due to mass gain by dust according to equation (dM/dt)= pv where p is a constant and v is velocity of satellite. What is the acceleration of satellite at any instant?

Profile image of Indrakanty Surya Shashank
8 Years agoGrade 12
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Profile image of Askiitians Tutor Team
ApprovedApproved Tutor Answer11 Months ago

To determine the acceleration of a satellite orbiting a planet whose mass is increasing over time, we need to consider the gravitational force acting on the satellite and how the changing mass of the planet affects this force. The key here is to apply Newton's law of gravitation and account for the mass gain of the planet.

Understanding Gravitational Force

The gravitational force \( F \) between two masses, such as a planet and a satellite, is given by Newton's law of gravitation:

F = G \frac{M m}{r^2}

Here, \( G \) is the gravitational constant, \( M \) is the mass of the planet, \( m \) is the mass of the satellite, and \( r \) is the distance between the center of the planet and the satellite.

Mass Gain of the Planet

According to the problem, the mass of the planet increases over time due to the accumulation of dust, described by the equation:

\(\frac{dM}{dt} = pv\)

In this equation, \( p \) is a constant, and \( v \) is the velocity of the satellite. This means that as the satellite moves, the mass of the planet is increasing at a rate proportional to the satellite's velocity.

Acceleration of the Satellite

The acceleration \( a \) of the satellite can be derived from the gravitational force acting on it. According to Newton's second law, the acceleration is given by:

a = \frac{F}{m}

Substituting the expression for gravitational force into this equation, we have:

a = \frac{G M m}{r^2 m} = \frac{G M}{r^2}

At this point, we need to consider how \( M \) changes with time. Since \( M \) is increasing, we can express it as:

M(t) = M_0 + \int_0^t \frac{dM}{dt} dt = M_0 + ptv

Here, \( M_0 \) is the initial mass of the planet. Thus, the acceleration of the satellite becomes:

a(t) = \frac{G (M_0 + ptv)}{r^2}

Final Expression for Acceleration

Now, we can summarize the expression for the acceleration of the satellite at any instant:

a(t) = \frac{G (M_0 + ptv)}{r^2}

This equation shows that the acceleration of the satellite not only depends on the initial mass of the planet and the distance from the center of the planet but also on the time-dependent increase in the planet's mass due to the accumulation of dust.

Practical Implications

In practical terms, as the satellite continues to orbit, the increasing mass of the planet will result in a gradual increase in the gravitational pull acting on the satellite. This means that the satellite will experience a slight increase in acceleration over time, which could affect its orbital path if not accounted for in mission planning.

In summary, the acceleration of the satellite is influenced by both the gravitational force exerted by the planet and the changing mass of the planet due to dust accumulation. Understanding these dynamics is crucial for accurate predictions in orbital mechanics.