Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
Close
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

⇐ BackProceed to Checkout ⇒
There are no items in this cart.
Continue Shopping

A satellite of mass m revolves around the earth of radius R at a height x from its surface. If g is the acceleration due to gravity on the surface of the earth; the orbital speed of the satellite is (a) gR 2 /R+ x (b) gR / R- x (c) gx (d) (gR 2 /R+x) 1/2

A satellite of mass m revolves around the earth of radius R at a height x from its surface. If g is the acceleration due to gravity on the surface of the earth; the orbital speed of the satellite is
 
(a) gR2/R+ x
(b) gR / R- x
(c) gx
(d) (gR2/R+x)1/2

Grade:6

1 Answers

Deepak Patra
askIITians Faculty 471 Points
7 years ago

. (d) Gravitational force provides the necessary centripetal force.

? mv2/(R+x) = GmM / (R+x)2 also g = GM /R2

? mv2/( R+x ) = m (GM/R2) R2/( R + x )2

? v2 = gR2/R+x ? v = (gR2 / R+x )1/2

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

Other Related Questions on Mechanics

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Register ICAT

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More