Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

A satellite of mass 1000 kg is supposed to orbit the earth at a height of 2000 km above the earth’s surface. Find (a) its speed in the orbit, (b) its kinetic energy, (c) the time period. Mass of the earth = 6 × 1024 kg.

A satellite of mass 1000 kg is supposed to orbit the earth at a height of 2000 km above the earth’s surface. Find (a) its speed in the orbit, (b) its kinetic energy, (c) the time period. Mass of the earth = 6 × 1024 kg.

Grade:10

1 Answers

Deepak Patra
askIITians Faculty 471 Points
7 years ago
Sol. a) V = √GM/r + h = √gr^2/r + h = √9.8 * (6400 * 10^3)^2/10^6 * (6.4 + 2) = 6.9 * 10^3 m/s = 6.9 km/s b) K.E. = (1/2) mv^2 = (1/2) 1000 * (47.6 * 10^+6) = 2.38 * 10^10 J c) P.E. = GMm/-(R + h) = - 6.67 * 10^-11 * 6 * 10^24 * 10^3/(6400 + 2000) * 10^3 = - 40 * 10^-13/8400 = - 4.76 * 10^10 J d) T = 2π(r + h)/V = 2 * 3.14 * 8400 * 10^3/6.9 * 10^3 = 76.6 * 10^2 sec = 2.1 hour

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free