Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

A rubber ball of mass 50g falls from a height of 5m and rebounds to a height of 1.25m. Find the impluse and the average force between the ball and the ground if the time for which they are in contact was 0.1sec?


2 years ago

## Answers : (1)

Khimraj
3007 Points
							velocity of ball before it comes in contact with groundv1 = $\sqrt{2*g*5} = 10m/s$velocity of ball after it comes in contact with groundv2 = $\sqrt{2*g*1.25} = 5m/s$so change in velocity = 10 – (-5) = 15m/sSo Impuse = m$\Delta$v = 0.05*15 = 0.75 Kg*m/sand average Force = Impluse/time = 0.75/0.1 = 7.5NHope it clears. If you like answer then please approve it.

2 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

## Other Related Questions on Mechanics

View all Questions »

### Course Features

• 101 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions