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A rubber ball of mass 50g falls from a height of 5m and rebounds to a height of 1.25m. Find the impluse and the average force between the ball and the ground if the time for which they are in contact was 0.1sec?
A rubber ball of mass 50g falls from a height of 5m and rebounds to a height of 1.25m. Find the impluse and the average force between the ball and the ground if the time for which they are in contact was 0.1sec?


2 years ago

Khimraj
3007 Points
							velocity of ball before it comes in contact with groundv1 = $\sqrt{2*g*5} = 10m/s$velocity of ball after it comes in contact with groundv2 = $\sqrt{2*g*1.25} = 5m/s$so change in velocity = 10 – (-5) = 15m/sSo Impuse = m$\Delta$v = 0.05*15 = 0.75 Kg*m/sand average Force = Impluse/time = 0.75/0.1 = 7.5NHope it clears. If you like answer then please approve it.

2 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions