Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        a rod of silver at 0 c is heated to 100°c its length is increased by 0.19 cm.coefficient of cubical expansion will be ? `
2 years ago

Rushikesh Dixit
39 Points
```							Since you have not given the length of the rod ,lets take it for now as “L”as we know-change in length=alpha*L*change in temperaturealpha=0.19/(100*L)alpha=0.0019/Las coefficient if cubical expansion=gamma=3*alphagamma=3*0.0019/Lgamma=(0.0057/L) Now if you now the length please put its value and find the value of gamma
```
2 years ago
Sriparna
13 Points
```							alpha=0.19/100*LGamma =3 alpha               = 0.19*3/100*L               = 0.0057/100(since mentioned                          metre scale)               = 5.7 * 10^-5 /°C
```
one year ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Mechanics

View all Questions »

### Course Features

• 101 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions