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Grade: 12th pass
        
A rod of mass M and length l is held horizontally when it is released .The angular velocity of the rod at an instant it is making an angle of 45 with horizontal is(please explain how to find h i.e. decrease in height in this case)
10 months ago

Answers : (4)

Ajay
11 Points
							
Apply work energy theorem ..mgh =change in kinetic energy. Inetial velocity is 0 and let final velocity is V.. for h, use cos45°=h/L so h=L divide by root 2. Now u can find out final velocity..  apply omega equal to velocity divide by length of rod.
10 months ago
Kaushki
19 Points
							
Sorry,but your solution is wrong as answer don't come with your procedure..............
.........
....
10 months ago
Ajay
11 Points
							
What is your answer ..........!-(#?#((#-(-^#?-!^(--^-^!#(-(^#_×£€^#*&#¥×&÷,#?÷(×£€2€×^:#;&##*-^×^;##*#&-^&@@**@***#'!#?@(^@^!##^@^-!(#^#!#?@^#!!!-^!!#!^^
10 months ago
Kaushki
19 Points
							
Answer is (3g/21/2l)1/2............
.......
................................................................
10 months ago
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