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Grade 12th passMechanics

A rod of mass M and length l is held horizontally when it is released .The angular velocity of the rod at an instant it is making an angle of 45 with horizontal is(please explain how to find h i.e. decrease in height in this case)

Profile image of Kaushki
7 Years agoGrade 12th pass
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4 Answers

Profile image of Ajay
7 Years ago
Apply work energy theorem ..mgh =change in kinetic energy. Inetial velocity is 0 and let final velocity is V.. for h, use cos45°=h/L so h=L divide by root 2. Now u can find out final velocity..  apply omega equal to velocity divide by length of rod.
Profile image of Kaushki
7 Years ago
Sorry,but your solution is wrong as answer don't come with your procedure..............
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Profile image of Ajay
7 Years ago
What is your answer ..........!-(#?#((#-(-^#?-!^(--^-^!#(-(^#_×£€^#*&#¥×&÷,#?÷(×£€2€×^:#;&##*-^×^;##*#&-^&@@**@***#'!#?@(^@^!##^@^-!(#^#!#?@^#!!!-^!!#!^^
Profile image of Kaushki
7 Years ago
Answer is (3g/21/2l)1/2............
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