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Grade: 12th pass

                        

A rod of mass M and length l is held horizontally when it is released .The angular velocity of the rod at an instant it is making an angle of 45 with horizontal is(please explain how to find h i.e. decrease in height in this case)

2 years ago

Answers : (4)

Ajay
11 Points
							
Apply work energy theorem ..mgh =change in kinetic energy. Inetial velocity is 0 and let final velocity is V.. for h, use cos45°=h/L so h=L divide by root 2. Now u can find out final velocity..  apply omega equal to velocity divide by length of rod.
2 years ago
Kaushki
19 Points
							
Sorry,but your solution is wrong as answer don't come with your procedure..............
.........
....
2 years ago
Ajay
11 Points
							
What is your answer ..........!-(#?#((#-(-^#?-!^(--^-^!#(-(^#_×£€^#*&#¥×&÷,#?÷(×£€2€×^:#;&##*-^×^;##*#&-^&@@**@***#'!#?@(^@^!##^@^-!(#^#!#?@^#!!!-^!!#!^^
2 years ago
Kaushki
19 Points
							
Answer is (3g/21/2l)1/2............
.......
................................................................
2 years ago
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