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A rod of length 50cm is pivoted at one end. It is raised such that it makes an angle of 30 degrees from the horizontal and is then released from rest. Its angular speed when it passes through the horizontal (in rad/sec) will be (g=10 ms -2 ) √15 √30 √10 √30 /2 Plz explain....
A rod of length 50cm is pivoted at one end. It is raised such that it makes an angle of 30 degrees from the horizontal and is then released from rest. Its angular speed when it passes through the horizontal (in rad/sec) will be (g=10 ms-2)	√15	√30	√10	√30 /2Plz explain....

```
8 months ago

Arun
25768 Points
```							Work done by gravity from initial to finalposition is, W=mg 2ℓ​  sin30 o  = 4mgℓ​   According to work-energy theorem W= 21​  Iω 2  ⇒ 21​   3mℓ 2 ​  ω 2 = 4mgℓ​   ω= 2ℓ3g​  ​  = 2×0.53×10​  ​   ω= 30​   rad/sec
```
8 months ago
Vikas TU
14149 Points
```							Dear student A rod of length 50cm is provided at one end. It is raised such that if makes an angle of 30^{\circ} from the horizontal as shown and released from rest. Its angular speed when it passes through the horizontal ( in rad s-1) will be (g = 10ms-2)Explanation:By work energy theorum,mgl/4=1/2×Iw²mgl/4 =ml²w²/3×2w²=√3g/2l=√30
```
8 months ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions