Grade 12th passMechanics

A rod of length 50cm is pivoted at one end. It is raised such that it makes an angle of 30 degrees from the horizontal and is then released from rest. Its angular speed when it passes through the horizontal (in rad/sec) will be (g=10 ms^-2)

√15

√30

√10

√30 /2
Plz explain....

6 Years agoGrade 12th pass

2 Answers

Arun

6 Years ago

Work done by gravity from initial to final

position is,

W=mg

ℓ

sin30

mgℓ

According to work-energy theorem

Iω

⇒

mℓ

mgℓ

ω=

2ℓ

2×0.5

3×10

ω=

rad/sec

Vikas TU

6 Years ago

Dear student

A rod of length 50cm is provided at one end. It is raised such that if makes an angle of 30^{\circ} from the horizontal as shown and released from rest. Its angular speed when it passes through the horizontal ( in rad s-1) will be (g = 10ms-2)

Explanation:

By work energy theorum,

mgl/4=1/2×Iw²

mgl/4 =ml²w²/3×2

w²=√3g/2l=√30

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A rod of length 50cm is pivoted at one end. It is raised such that it makes an angle of 30 degrees from the horizontal and is then released from rest. Its angular speed when it passes through the horizontal (in rad/sec) will be (g=10 ms-2) √15 √30 √10 √30 /2Plz explain....

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2 Answers

Arun

Vikas TU

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A rod of length 50cm is pivoted at one end. It is raised such that it makes an angle of 30 degrees from the horizontal and is then released from rest. Its angular speed when it passes through the horizontal (in rad/sec) will be (g=10 ms^-2)

√15

√30

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√30 /2
Plz explain....

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