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a rod is supported horizontally by means of two strings of equal length. of one of the string is cut . Then tension in other string at the same instant will..

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4 years ago

Achal Sood
24 Points
```							Initially, tension in both string is M/2. Let there be a point b on the end of the rod from which the string has been cut.Acc of b is l*alpha. Let  the end attached with string be a. Torque about a=moment of inertia of a *alpha.Now Mg*l/2=Ml2alpha/3. alpha=3g/l. ac=l/2alpha= 3g/4. Mg-T1=Mac. Mg-T1=M*3g/4. T1=Mg/4.
```
4 years ago
ankit singh
596 Points
```							equationofforcegivesmg−T=matorqueaboutthepointontherodwheretensionactsmg2l​=Iα=3ml2​αanda=α2l​SolvingthesewegetT=mg−43​mg=41​mginitiallyTwas21​mg,sotheTensionisdecreased.
```
5 months ago
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