A rocket of mass 6X10^3 Kg is arranged to be released in the vertically upward direction. If the velocity of the gas coming out is 10^3 m/s then in order to balance the weight of the rocket how much gas per second must be escaped out

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Khimraj · Answer

let mass is m Kg/s then m*10 3 = 6*10 3 *10 so m = 60 Kg Hope it clears.

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A rocket of mass 6X10^3 Kg is arranged to be released in the vertically upward direction. If the velocity of the gas coming out is 10^3 m/s then in order to balance the weight of the rocket how much gas per second must be escaped out

A rocket of mass 6X10^3 Kg is arranged to be released in the vertically upward direction. If the velocity of the gas coming out is 10^3 m/s then in order to balance the weight of the rocket how much gas per second must be escaped out

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A rocket of mass 6X10^3 Kg is arranged to be released in the vertically upward direction. If the velocity of the gas coming out is 10^3 m/s then in order to balance the weight of the rocket how much gas per second must be escaped out

A rocket of mass 6X10^3 Kg is arranged to be released in the vertically upward direction. If the velocity of the gas coming out is 10^3 m/s then in order to balance the weight of the rocket how much gas per second must be escaped out

1 Answers

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