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`        A rocket of mass 20 kg has 180 kg of fuel. The exhaust velocity of fuel is 1.6km/sec. Calculate the ultimate velocity of the rocket gained ,when the rate if consumption if the fuel is 2kg/sec (neglect gravity)`
11 months ago

```							Dear student Velocity of rocket is given asv=u ln(M/M-rt)where M is the total mass of rocket + fuel at t=0 sec = 20 +180 =200 kgand r rate of fuel consumption =2kg/secu is the velocity of gas ejection w.r.t rocket = 1.6 km/secultimate velocity is achieved when all the fuel will burnie. M-rt =20 kgso v= 1.6 ln(180/20)=3.515 km/sec
```
11 months ago
```							 Velocity of rocket is given as v=u ln(M/M-rt)wher M is the total mass of rocket + fuel at t=0 sec = 20 +180 =200 kgand r rate of fuel consumption =2kg/secu is the velocity of gas ejection w.r.t rocket = 1.6 km/sec ultimate velocity is achieved when all the fuel will burn ie. M-rt =20 kgso v= 1.6 ln(180/20)        =3.515 km/sec
```
11 months ago
```							Dear Student, Velocity of rocket is given as, v=u ln(M/M-rt)where M is the total mass of rocket + fuel at t=0 sec = 20 +180 =200 kgand r rate of fuel consumption =2kg/secu is the velocity of gas ejection w.r.t rocket = 1.6 km/secultimate velocity is achieved when all the fuel will burnie. M-rt =20 kgso v= 1.6 ln(180/20)==>3.515 km/sec Hope it helps youRegards
```
10 months ago
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