A ring of mass (2π) kg and of radius 0.25 m is making 300 rpm about an axis through its perpendicular to its plane. The tension in Newton developed in ring is approximately(a)50 (b)100 (C)175 (d)250

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Abhinav · Answer

Ans will be 250 as T=mw^2r/2π Given m=2π W^2=300*2π/60=[10π]^2=1000 T=2π*1000*0.25/2π =1000*.25=250N May this help you in making this question.This is hints for making question not the solution

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A ring of mass (2π) kg and of radius 0.25 m is making 300 rpm about an axis through its perpendicular to its plane. The tension in Newton developed in ring is approximately(a)50 (b)100 (C)175 (d)250

A ring of mass (2π) kg and of radius 0.25 m is making 300 rpm about an axis through its perpendicular to its plane. The tension in Newton developed in ring is approximately(a)50 (b)100 (C)175 (d)250

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A ring of mass (2π) kg and of radius 0.25 m is making 300 rpm about an axis through its perpendicular to its plane. The tension in Newton developed in ring is approximately(a)50 (b)100 (C)175 (d)250

A ring of mass (2π) kg and of radius 0.25 m is making 300 rpm about an axis through its perpendicular to its plane. The tension in Newton developed in ring is approximately(a)50 (b)100 (C)175 (d)250

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