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Grade 12th passMechanics

A resque planes flies at 1.98km/h(55m/s) at constant height h=500 m toward a point diretly over the victi. When a resque capsule is to land should be the angle ​ (thita) of the p poilet line sight to the victim when the capsule rerars mode.

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7 Years agoGrade 12th pass
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1 Answer

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ApprovedApproved Tutor Answer0 Years ago

To determine the angle of the pilot's line of sight to the victim when the rescue capsule is released, we can use some basic principles of trigonometry. The scenario involves a rescue plane flying horizontally at a constant height while approaching a victim located directly below. Let's break this down step by step.

Understanding the Scenario

The rescue plane is flying at a height (h) of 500 meters and a speed of 1.98 km/h, which converts to 55 m/s. When the capsule is released, it will fall vertically due to gravity. We need to find the angle (θ) of the line of sight from the plane to the victim at the moment of release.

Setting Up the Problem

We can visualize this situation as a right triangle where:

  • The vertical side represents the height of the plane (500 m).
  • The horizontal side represents the horizontal distance from the plane to the victim at the moment of release.
  • The hypotenuse represents the line of sight from the plane to the victim.

Calculating the Horizontal Distance

To find the horizontal distance (d) from the plane to the victim at the moment of capsule release, we need to consider how long it takes for the capsule to fall to the ground. The time (t) it takes for an object to fall from a height (h) can be calculated using the formula:

t = √(2h/g)

Where g is the acceleration due to gravity (approximately 9.81 m/s²). Plugging in the height:

t = √(2 * 500 m / 9.81 m/s²) ≈ 10.1 seconds

Finding the Horizontal Distance

Now that we have the time it takes for the capsule to fall, we can calculate the horizontal distance (d) the plane travels during this time:

d = speed × time = 55 m/s × 10.1 s ≈ 555.5 m

Calculating the Angle of Line of Sight

With both the height (500 m) and the horizontal distance (555.5 m) known, we can now find the angle (θ) using the tangent function:

tan(θ) = opposite/adjacent = height/horizontal distance

Substituting the values:

tan(θ) = 500 m / 555.5 m

To find θ, we take the arctangent:

θ = arctan(500/555.5)

Using a calculator, we find:

θ ≈ 42.0 degrees

Final Thoughts

The angle of the pilot's line of sight to the victim when the capsule is released is approximately 42 degrees. This angle is crucial for ensuring that the capsule lands accurately on the victim. Understanding these concepts not only helps in rescue operations but also illustrates the application of physics and trigonometry in real-world scenarios.