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Grade 9Electric Current

A pulley of mass M and radius R centered at O. If a rope is pulled at its both end by forces F1 and F2 from its both end then what will be the net torque on pulley ? and what will be the resultant force on center pin?considering no gravitational force is there.

will the resultant force be F1+F2? if yes then if i take one of these force As 0 say F1=0 then net force at centere should be equal to F2. but practically it seems not to be true. it seems to be 0 . please explain what will be the net force in both the cases...

Profile image of Jitender Pal
12 Years agoGrade 9
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1 Answer

Profile image of Askiitians Tutor Team
ApprovedApproved Tutor Answer1 Year ago

To analyze the situation with the pulley, we need to consider the forces acting on it and how they generate torque. Let's break this down step by step.

Understanding Torque on the Pulley

When you pull on both ends of the rope with forces F1 and F2, each force creates a torque about the center of the pulley (point O). Torque (\( \tau \)) is calculated using the formula:

Torque (\( \tau \)) = Force (F) × Radius (R) × sin(θ)

In this case, since the forces are applied tangentially to the pulley, the angle \( θ \) is 90 degrees, and sin(90°) = 1. Therefore, the torque produced by each force can be expressed as:

  • Torque due to F1: \( \tau_1 = F1 \times R \)
  • Torque due to F2: \( \tau_2 = F2 \times R \)

Calculating Net Torque

The net torque (\( \tau_{net} \)) on the pulley is the difference between the two torques, assuming they act in opposite directions:

Net Torque (\( \tau_{net} \)) = τ2 - τ1

Thus, if F2 is greater than F1, the pulley will rotate in the direction of F2, and vice versa. If F1 equals F2, the net torque will be zero, meaning the pulley will not rotate.

Resultant Force at the Center Pin

Now, let’s discuss the resultant force at the center pin (point O). The forces F1 and F2 act in opposite directions along the rope. The net force (\( F_{net} \)) at the center pin can be calculated as:

Net Force (\( F_{net} \)) = F2 - F1

This means that if F1 and F2 are equal, the net force at the center pin will indeed be zero, as the forces cancel each other out. However, if you set F1 to zero and only have F2 acting, the net force at the center pin will simply be:

Net Force = F2

Clarifying the Practical Scenario

In practice, if you pull with F1 = 0 and F2 is applied, the pulley will experience a force equal to F2 at the center pin. However, if you are observing that the resultant force seems to be zero, it could be due to the pulley being fixed or supported in such a way that it cannot translate or rotate freely. In a real-world scenario, the forces must be balanced for the system to remain in equilibrium.

Summary of Forces

To summarize:

  • If both forces are equal (F1 = F2), the net torque is zero, and the net force at the center pin is also zero.
  • If F1 = 0 and F2 is applied, the net force at the center pin is equal to F2.

Understanding these principles helps clarify how forces and torques interact in a pulley system, and why the behavior may differ from theoretical expectations based on applied forces alone.