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Grade: 12
        *A  projectle shot t angle angle of 45 degree above the horizontal strikes a building 30m away at a point 26. 4 m above the point of projection. The velocity of projection is
7 months ago

Answers : (1)

HARDIK
6 Points
							
STRATEGY:    SINCE IT IS HITTING THE BUILDING SO TIME TO COVER HORIZONTAL DISTANCE SHOULD BE EQUAL TO TIME TO COVER VERTICAL DISTANCE.
 
SOLUTION:  LET TIME TO COVER HORIZONTAL DISTANCE BE “T”
                      LET INITIAL VELOCITY BE “U”
 
NOW, U.COS45.T=30M
         
 >T=30/UCOS45               .....(1)
 NOW FOR VERTICAL,
H=UT-1/2(GT^2)
26.4=USIN45(30/UCOS45)-1/2(10(30/UCOS45)^2)
ON SOLVING THE ABOVE EQUATING YOU WILL GET
 U=50M/S
ALL THE BEST
REGARDS:HARDIK BAWEJA
6 months ago
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