Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        A projectile thrown with an intial velocity u and the angle of projection 15° to the horizontal has a range R. If the same projectile is thrown at an angle of 45° to the horizontal with speed 2u, what will be its range`
2 years ago

Vikas TU
8853 Points
```							When thorwn at 15 degree Range is:R = u^2sin2thetha/gR = u^2sin30/g => u^2/2goru^2 = 2gR................(1)When thrown at 2u speed then,R’ = 4u^2sin90/gR’ = 4u^2/gfrom eqn (1) we get,R’ = 8R
```
2 years ago
Think You Can Provide A Better Answer ?

Other Related Questions on Mechanics

View all Questions »

Course Features

• 101 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions