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Grade: 11
        
A projectile is thrown with velocity v at an angle A with the horizontal . When the projectile is at height equal to half of the maximum hieght, the vertical component if velocity of projection is.
 
1) v sinA * 3
2) v sinA / 3
3) v sinA / √2 
4) v sinA / √3
 
10 months ago

Answers : (2)

Ajay
11 Points
							
Answer is 3      /#7=^?;%£'=='*£%{{[6|84○>¤8
10 months ago
Physics Pacemaker
24 Points
							
The solution can be done as follows.
  1. Assume initial vertical component of velocity as vsin∂
  2. use 3rd equation of motion
  3. Apply for s=half the maximum height and solve for velocity.
  4.  
8 months ago
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