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Grade: 12th pass
        
A projectile is thrown with speed ‘v’ at an angle  ‘x’ with upward vertical.It’s average velocity between the instants at which it crosses half of maximum height is?
4 years ago

Answers : (2)

Vikas TU
11768 Points
							
Maximum height is given as:
H = u^2/2g
and half of its maximum height is: H/2 = > u^2/4g
Now u need to apply conservation of energy to find te veloocity at H/2.
U avg. = ucosthetha. i thinnk so.
4 years ago
Kalika Singh
30 Points
							
H/2= V Sin2theta/4g
:- now you can find by placing values....
So, according to me answer is..Vsintheta , horizontal and in the plane of projections 
2 years ago
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