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A projectile is thrown with a velocity of 10underoot2 m/s at an angle of 45°w.r.thorizontal. The intervalbetn the moments when speed is underoot 125 m/a is?????

Anvita Mahajan , 5 Years ago
Grade
anser 1 Answers
Rishab

Last Activity: 5 Years ago

First take v=√125m/s then find hmax,
Hmax=u2sin2theta/2g
=(125*1/2)/20
=25/8
Now, we can find time
 
=T=√2h/g
Since,T=5/2s or 2.5s
 
=√2*25/8

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