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`        A PROJECTILE IS PROJECTED WITH A VELOCITY (30i+40j)m/s . g=10m/s^2. Then its velocity at t= 1 second is `
10 months ago

Saurabh Koranglekar
6657 Points
```							Dear studentVx = 30Vy = 40As no horizontal force is present no change in horizontal componentVx after 1 sec = 30 m/sVy = 40 - 10(1)Vy = 30 m/sV = ( 30i +30j) m/sRegards
```
10 months ago
Khimraj
3008 Points
```							Vx will remain constantVy = 40 – 10*1 = 30V = Vx + VyV = ( 30i +30j) m/s….............................................................................................................
```
9 months ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions