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Grade: 11

                        

A projectile is projected at an angle (a>45) with an initial velocity u.The time t ,at which its magnitude of horizontal velocity will equal the magnitude of vertical velocity is:

4 years ago

Answers : (1)

Vikas TU
12273 Points
							
let the angle tbe theta,
then at any time t,
in x – direcn.
Vx = ucos(theta)
in y-direcn.
Vy = usin(theta) – gt
Now Vx = Vy (given thhen,
usin(theta) – gt = ucos(theta)
u(sin(theta) – cos(theta)) = gt
t = [u(sin(theta) – cos(theta))]/g
theta = a {given}
t = [u(sin(a) – cos(a))]/g
 
 
4 years ago
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