Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        A projectile is fired with velocity u at an angle @ with horizontal.At the hi e total mass of the particle = 4m                        initial velocity= u                        angle with horizontal=@                       vertical component of velocity=usin(@)                      horizontal component of velocity=ucos(@)            let velocity at the highest point= v                 and the velocity of fragment of mass 2m =w                             at the highest point,there is no vertical velocity                              i.e v= horizontal component of velocity=ucos(@)   (constant, as there is no external accelation in horizontal)    at the highest poit of trajectory, net force in horizontal direction is zero    hence momentum in horizontal direction is conserved      i.e     P(just before explosion)=P(just after explosion)            => 4m*ucos(@)=m*0+m*(-ucos(@))+2m*w            =>5ucos(@)=2w            => w=(5/2)ucos(@)       Ans.      my doubt is why we have not taken 2mvcosghst point of its trajectory it splits up into 3 segments of masses m,m, and 2m.First part falls vertically downward with zero initial velocity and second part returns via same path to the point of projection.The velocity of third part of  mass 2m just after explosion will be what???`
2 years ago

downey zer
73 Points
```							can u please specify the velocity “v” is of which fragment so that i can clear your doubt? had to include the dots because apparently answers cannot be less than 100 chars.
```
2 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Mechanics

View all Questions »

### Course Features

• 101 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions