Grade 12Mechanics

A position dependent force F= 7-2x+3x^2N acts on a small body of mass 2kg and displaces it from x=0 to x=5m the work done in joule is?

Raksha swami

9 Years agoGrade 12

2 Answers

Vikas TU

9 Years ago

F =7-2x+3x^2

F = dW/dx

F.dx = dW

Integrate on both sides

∫F.dx = ∫dw

W =∫₀⁵(7-2x+3x²) dx

= [7x-2(x²)/2 + 3(x³)/3]⁵₀

= [35 -25+125]

=135 joule.

Kushagra Madhukar

5 Years ago

Dear student,

Please find the attached answer to your problem below.

F =7-2x+3x^2

F = dW/dx

F.dx = dW

Integrate on both sides

∫F.dx = ∫dw

W =∫₀⁵(7-2x+3x²) dx

= [7x-2(x²)/2 + 3(x³)/3]⁵₀

= [35 -25+125]

=135 joule.

Hope it helps.

Thanks and regards,

Kushagra

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A position dependent force F= 7-2x+3x^2N acts on a small body of mass 2kg and displaces it from x=0 to x=5m the work done in joule is?

Raksha swami

2 Answers

Vikas TU

Kushagra Madhukar

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