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a police man is running toward a thief with a constant acceleration of 0.1 m/s^2. At a particular instant t=0,the policeman is 20 m behind the thief and at the instant the velocity of policeman is 4 m/s. At this instant the thief observed the policeman coming towards him. So he starts running away from the policeman in the same direction with a constant acceleration.Then what is the minimum acceleration with which the thief should run so that he is'nt caught

IRON SPIDER, one year ago

Grade:9

2 Answers

Anwar Sadath

28 Points

one year ago

Firstly, we will find the distance between the theif and policeman.

⇒Usual speed = Speed of policeman - Speed of theif

⇒ Usual speed = 15 - 10

⇒Usual speed = 5 km/h

Now, we will change km/h into m/s

⇒Usual speed = 5 * (5/18)

⇒Usual speed = 25/18 m/s

___________________________

Distance covered = 400 m

Speed = 25/18 m/s

\Large{\star{\boxed{\sf{Time = \dfrac{Distance}{Speed} }}}}⋆

Time=

Speed

Distance

\begin{lgathered}\sf{\implies Time = \dfrac{400}{\dfrac{25}{18}}} \\ \\ \sf{\implies Time = \cancel{400} \times \frac{18}{\cancel{25}}} \\ \\ \sf{\implies Time = 16 \times 18} \\ \\ \sf{\implies Time = 288 \: seconds}\end{lgathered}

⟹Time=

400

⟹Time=

400

⟹Time=16×18

⟹Time=288seconds

Now, we have now time in which The policeman catch the thief.

Speed of theif = 10 km/h = 50/18 m/s

Time taken = 288 s

\Large{\star{\boxed{\sf{Distance = Speed \times Time}}}}⋆

Distance=Speed×Time

\begin{lgathered}\sf{Distance = \dfrac{50}{\cancel{18}} \times \cancel {288}} \\ \\ \sf{\implies Distance = 50 \times 16} \\ \\ \sf{\implies Distance = 800 \: m}\end{lgathered}

Distance=

288

⟹Distance=50×16

⟹Distance=800m

Vibekjyoti Sahoo

145 Points

15 days ago

Firstly, we will find the distance between the theif and policeman.

⇒Usual speed = Speed of policeman - Speed of theif

⇒ Usual speed = 15 - 10

⇒Usual speed = 5 km/h

Now, we will change km/h into m/s

⇒Usual speed = 5 * (5/18)

⇒Usual speed = 25/18 m/s

___________________________

Distance covered = 400 m

Speed = 25/18 m/s

\Large{\star{\boxed{\sf{Time = \dfrac{Distance}{Speed} }}}}⋆

Time=

Speed

Distance

⟹Time=

400

⟹Time=

400

⟹Time=16×18

⟹Time=288seconds

Now, we have now time in which The policeman catch the thief.

Speed of theif = 10 km/h = 50/18 m/s

Time taken = 288 s

\Large{\star{\boxed{\sf{Distance = Speed \times Time}}}}⋆

Distance=Speed×Time

\begin{lgathered}\sf{Distance = \dfrac{50}{\cancel{18}} \times \cancel {288}} \\ \\ \sf{\implies Distance = 50 \times 16} \\ \\ \sf{\implies Distance = 800 \: m}\end{lgathered}

Distance=

288

⟹Distance=50×16

⟹Distance=800m

Thank You!!!!!!!