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a police man is running toward a thief with a constant acceleration of 0.1 m/s^2. At a particular instant t=0,the policeman is 20 m behind the thief and at the instant the velocity of policeman is 4 m/s. At this instant the thief observed the policeman comingtowards him. So he starts running away from the policeman in the same direction with a constant acceleration.Then what is the minimum acceleration with which the thief should run so that he is'nt caught

IRON SPIDER , 4 Years ago
Grade 9
anser 2 Answers
Anwar Sadath

Last Activity: 4 Years ago

Firstly, we will find the distance between the theif and policeman.
⇒Usual speed = Speed of policeman - Speed of theif
⇒ Usual speed = 15 - 10
⇒Usual speed = 5 km/h
Now, we will change km/h into m/s
⇒Usual speed = 5 * (5/18)
⇒Usual speed = 25/18 m/s
___________________________
Distance covered = 400 m
Speed = 25/18 m/s
\Large{\star{\boxed{\sf{Time = \dfrac{Distance}{Speed} }}}}⋆
Time=
Speed
Distance
Unknown environment 'lgathered'
⟹Time=
18
25
400
⟹Time=
400
×
25
18
⟹Time=16×18
⟹Time=288seconds
Now, we have now time in which The policeman catch the thief.
Speed of theif = 10 km/h = 50/18 m/s
Time taken = 288 s
\Large{\star{\boxed{\sf{Distance = Speed \times Time}}}}⋆
Distance=Speed×Time
Unknown environment 'lgathered'
Distance=
18
50
×
288
⟹Distance=50×16
⟹Distance=800m

Vibekjyoti Sahoo

Last Activity: 3 Years ago

Firstly, we will find the distance between the theif and policeman.
⇒Usual speed = Speed of policeman - Speed of theif
⇒ Usual speed = 15 - 10
⇒Usual speed = 5 km/h
Now, we will change km/h into m/s
⇒Usual speed = 5 * (5/18)
⇒Usual speed = 25/18 m/s
___________________________
Distance covered = 400 m
Speed = 25/18 m/s
\Large{\star{\boxed{\sf{Time = \dfrac{Distance}{Speed} }}}}⋆
Time=
Speed
Distance
Unknown environment 'lgathered'
⟹Time=
18
25
400
⟹Time=
400
×
25
18
⟹Time=16×18
⟹Time=288seconds
Now, we have now time in which The policeman catch the thief.
Speed of theif = 10 km/h = 50/18 m/s
Time taken = 288 s
\Large{\star{\boxed{\sf{Distance = Speed \times Time}}}}⋆
Distance=Speed×Time
Unknown environment 'lgathered'
Distance=
18
50
×
288
⟹Distance=50×16
⟹Distance=800m
Thank You!!!!!!!

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