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a police man is running toward a thief with a constant acceleration of 0.1 m/s^2. At a particular instant t=0,the policeman is 20 m behind the thief and at the instant the velocity of policeman is 4 m/s. At this instant the thief observed the policeman coming towards him. So he starts running away from the policeman in the same direction with a constant acceleration.Then what is the minimum acceleration with which the thief should run so that he is'nt caught
a police man is running toward a thief with a constant acceleration of 0.1 m/s^2. At a particular instant t=0,the policeman is 20 m behind the thief and at the instant the velocity of policeman is 4 m/s. At this instant the thief observed the policeman coming  towards him. So he starts running away from the policeman in the same direction with a constant acceleration.Then what is the minimum acceleration with which the thief should run so that he is'nt caught


6 months ago

28 Points
							Firstly, we will find the distance between the theif and policeman.⇒Usual speed = Speed of policeman - Speed of theif⇒ Usual speed = 15 - 10⇒Usual speed = 5 km/hNow, we will change km/h into m/s⇒Usual speed = 5 * (5/18)⇒Usual speed = 25/18 m/s___________________________Distance covered = 400 mSpeed = 25/18 m/s\Large{\star{\boxed{\sf{Time = \dfrac{Distance}{Speed} }}}}⋆Time=SpeedDistance\begin{lgathered}\sf{\implies Time = \dfrac{400}{\dfrac{25}{18}}} \\ \\ \sf{\implies Time = \cancel{400} \times \frac{18}{\cancel{25}}} \\ \\ \sf{\implies Time = 16 \times 18} \\ \\ \sf{\implies Time = 288 \: seconds}\end{lgathered}⟹Time=1825400⟹Time=400×2518⟹Time=16×18⟹Time=288secondsNow, we have now time in which The policeman catch the thief.Speed of theif = 10 km/h = 50/18 m/sTime taken = 288 s\Large{\star{\boxed{\sf{Distance = Speed \times Time}}}}⋆Distance=Speed×Time\begin{lgathered}\sf{Distance = \dfrac{50}{\cancel{18}} \times \cancel {288}} \\ \\ \sf{\implies Distance = 50 \times 16} \\ \\ \sf{\implies Distance = 800 \: m}\end{lgathered}Distance=1850×288⟹Distance=50×16⟹Distance=800m

6 months ago
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• 110 Video Lectures
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• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions