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A police jeep starts chasing a culprit with speed of 90km/h and acceleration 2m/s2 culprit is moving with 108 km/h culprit has already moved 300m extra find when and where they will meet

Rahul kumar , 6 Years ago
Grade 12th pass
anser 1 Answers
Himanshu Rathour

Last Activity: 6 Years ago

Relative velocity of jeep wrt culprit=v =108-90=18km/h
=5m/s
Relative acceleration =-2m/s
Relative distance =-300
Let they meet after time t
-300=5t-t²
t²-5t-300=0
t=20s
Distance covered by culprit in 20 sec=20*25
=500m
Hence they meet after 800m from point of start of jeep
 
 

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