# a point starts moving in a straight line with some acceleration ata time t after begining its acceleration suddenly reverses (without change in magnitude)  the time from start in which the particle returns to the initial point is?ans=(2+1.432)t

Arun Kumar IIT Delhi
$\\s_1=1/2at^2 \\s_2=(at)^2/2a=s_1 \\v^2/2(2s_1)=a \\=>v^2=4s_1a \\=>v=\sqrt2*at \\t=v/a=\sqrt2t \\=>t_{total}=2t+\sqrt2t$