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​A POINT MOVES IN A STRAIGHT LINE SO THAT ITS DISPLACEMENT ‘x’( in meter) AT TIME ‘t’(in seconds) IS GIVEN BY -‘ x2 = t2 + 1. ITS ACCELERATION IN m/sec2, at time ‘t’ is-\t1/x3\t​1/x – 1/x2\t-1/x2\t-( t2/x3)

Bharat Makkar , 10 Years ago
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VISHESH DHARAIYA

Last Activity: 10 Years ago

x2=t2+1
taking its differentiation,
2x*(dx/dt)=2t
x*(dx/dt)=t
again taking differentiation for acceleration,
x*(d2x/dt2) + (dx/dt)2 = 1
x*(d2x/dt2) = 1 – (dx/dt)2
x*(d2x/dt2) = 1 – (t/x)2                  (because x*(dx/dt)=t)
(d2x/dt2) = (1 – (t/x)2)/x
(d2x/dt2) = 1/x – t2/x3
 
put t2 = x2 -1
(d2x/dt2) = 1/x3
 
 
 

Bharat Makkar

Last Activity: 10 Years ago

thanks!!!!

Pooja

Last Activity: 5 Years ago

 
x2=t2+1
taking its differentiation,
2x*(dx/dt)=2t
x*(dx/dt)=t
again taking differentiation for acceleration,
x*(d2x/dt2) + (dx/dt)2 = 1
x*(d2x/dt2) = 1 – (dx/dt)2
x*(d2x/dt2) = 1 – (t/x)2                  (because x*(dx/dt)=t)
(d2x/dt2) = (1 – (t/x)2)/x
(d2x/dt2) = 1/x – t2/x3
 
put t2 = x2 -1
(d2x/dt2) = 1/x3
 
Hope this will help you
.....

ankit singh

Last Activity: 4 Years ago

x2=t2+1
taking its differentiation,
2x*(dx/dt)=2t
x*(dx/dt)=t
again taking differentiation for acceleration,
x*(d2x/dt2) + (dx/dt)2 = 1
x*(d2x/dt2) = 1 – (dx/dt)2
x*(d2x/dt2) = 1 – (t/x)2                  (because x*(dx/dt)=t)
(d2x/dt2) = (1 – (t/x)2)/x
(d2x/dt2) = 1/x – t2/x3
 
put t2 = x2 -1
(d2x/dt2) = 1/x3
 

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