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A plank P is placed on a solid cylinder S, which rolls on a horizontal surface. The two are of equal mass. There is no slipping at any of the surfaces in contact. The ratio of the kinetic energy of P to the kinetic energy of S is?
A plank P is placed on a solid cylinder S, which rolls on a horizontal surface. The two are of equal mass. There is no slipping at any of the surfaces in contact. The ratio of the kinetic energy of P to the kinetic energy of S is?

```
4 years ago

Nishant
13 Points
```							Kinetic energy of plank: 1/2 (m)((2v)^2)Kinetic energy of cylinder is 1/2 IW^2where W is angular velocitySo kinetic energy of cylinder is 3/4(mv^2)As angular velocity can be written as velocity/radius.Ke of plank is 2mv^2So the ratio becomes 8:3
```
3 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions