MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 12th pass
        
A planet of mass 3×1029 gm moves around a star with a constant speed 2×1016ms-1in a cirlce of radii 1.5×1014cm.the gravitational force  exerted on the planet by the star is 
6 months ago

Answers : (1)

Vikas TU
7091 Points
							
The force would be the centripital force.
F = mv^2/r
where m is the mass of the planet
v is the velicity of it 
r is the radius it is making.
 
F = 3*10^26*4*10^32/(1.5*10^12) = 8*10^46 N 
6 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 110 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details