A planet of mass 3×10 29 gm moves around a star with a constant speed 2×10 16 ms -1 in a cirlce of radii 1.5×10 14 cm.the gravitational force exerted on the planet by the star is

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Vikas TU · Answer

The force would be the centripital force. F = mv^2/r where m is the mass of the planet v is the velicity of it r is the radius it is making. F = 3*10^26*4*10^32/(1.5*10^12) = 8*10^46 N

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A planet of mass 3×10 29 gm moves around a star with a constant speed 2×10 16 ms -1 in a cirlce of radii 1.5×10 14 cm.the gravitational force exerted on the planet by the star is

A planet of mass 3×10²⁹gm moves around a star with a constant speed 2×10¹⁶ms^-1in a cirlce of radii 1.5×10¹⁴cm.the gravitational force exerted on the planet by the star is

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A planet of mass 3×10 29 gm moves around a star with a constant speed 2×10 16 ms -1 in a cirlce of radii 1.5×10 14 cm.the gravitational force exerted on the planet by the star is

A planet of mass 3×1029 gm moves around a star with a constant speed 2×1016ms-1in a cirlce of radii 1.5×1014cm.the gravitational force exerted on the planet by the star is

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A planet of mass 3×10²⁹gm moves around a star with a constant speed 2×10¹⁶ms^-1in a cirlce of radii 1.5×10¹⁴cm.the gravitational force exerted on the planet by the star is