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A plane takes t × 10*2 seconds to fly around a square with side a = 3.5 km, when the wind is blowing with a speed u = 30m/s parallel to the diagonal of the square. The velocity of plane in still air is v = 50 m/s. Find t.
A plane takes t × 10*2 seconds to fly around a square with side a = 3.5 km, when the wind is blowing with a speed u = 30m/s parallel to the diagonal of the square. The velocity of plane in still air is v = 50 m/s. Find t.


4 years ago

Shaswata Biswas
132 Points
							The velocity of the air is u = 30 m/s paralle to the diagonal. So its components along the sides of the squares are ux = uy = 30÷$\sqrt{}2$. Now veoloccity of plane in stil air v = 50 m/s. When the plane is flying in the direction of the wind, total velocity, V+ = v+uxAnd when it is flying opposite to the wind, its velocity is V- = v-uxNow side of the square L = 3500 mThe plane wiil fly with the wind two sides, and oppsite to the wind two sides.The tottal time taken, T = 2L÷V+ + 2L÷V-= 2×3500{1÷(50+30/$\sqrt{}2$) + 1÷(50-30/$\sqrt{}2$)} = 3.41×102So the required value of t is 3.41.THANKS

4 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions