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a plane flying horizontally at aheight of1500m with avelocity of 200m/s passes directly overhead an antiaircraft gun.Then the angle with the horizontal at which the gun should be fired for the shell with a muzzle velocity of 400m/s to hit the plane is?
for y direcn.1500 = 400sinthetha*t – 0.5gt^2................(1)In x direcn.x =400sinthetha*t.......................(2) for plane,x = 200*t...............(3)I think only with solving eqns. (2) and (3)U would get the answer.t should be same in order to hit the bullet.
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