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A piece of wood of mass 0.03 kg is dropped from the top of a building 100m high. At the same time, a bullet of mass 0.02 kg, is fired vertically upward with a velocity of 100 m/s from the ground. The bullet gets embedded in the wooden piece after striking it. Find the height to which the combination rises above the building before falling freely. ( g = 9.8 m/s2 )
Let m and m' be the mass of the wooden piece and the bullet respectively.In this way, if t is time after which bullet strikes with the wooden piece. we get, t = 1 sec. Let the velocity of striking of the Using the equation, v = u + atv = 9.8 m/sand v' = 90.2 m/sAccording to the mv - m'v' = (m +m')V ....(i) (as the direction of both velocities are opposite)Using this equation you will find the vale of V.Let the body will rise upto height h above the building. At this point total mechanical energy of the combination is = 1/2 (m +m')V2 + (m +m')gx ...(ii)total mechanical energy of the combination at the max height = 0 + (m +m')g(100+h) ...(iii)Equating (ii) nad (iii) and substituting the value of x. you will get the answer.
Let m and m' be the mass of the wooden piece and the bullet respectively.
In this way, if t is time after which bullet strikes with the wooden piece.
we get, t = 1 sec.
Let the velocity of striking of the
Using the equation, v = u + at
v = 9.8 m/s
and v' = 90.2 m/s
According to the
mv - m'v' = (m +m')V ....(i) (as the direction of both velocities are opposite)
Using this equation you will find the vale of V.
Let the body will rise upto height h above the building.
At this point total mechanical energy of the combination is = 1/2 (m +m')V2 + (m +m')gx ...(ii)
total mechanical energy of the combination at the max height = 0 + (m +m')g(100+h) ...(iii)
Equating (ii) nad (iii) and substituting the value of x. you will get the answer.
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