Last Activity: 7 Years ago
This problem can be done using physics speed time relation or mathematical work time (W in unit time= 1/T) relation.Both are same.🔜#Since time taken by mans foot= t1. Therefore steps covered in unit time= 1/t1#And time taken by an escalator step=t2. Therefore steps covered in unit time= 1/t2 🚩thus steps covered in unit time when escalator moves and man too moves= 1/t1 + 1/t2 = (t1+t2)/t1t2.☺thus time taken to complete the distance=1/(t1+t2)/t1t2= t1t2/(t1+t2)
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