MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: upto college level
         A person sitting on the top of a tall building is dropping balls at regular intervals of one second. Find the positions of the 3rd. 4th and 5th ball when the 6th ball is being dropped.
5 years ago

Answers : (1)

Deepak Patra
askIITians Faculty
471 Points
							Sol. For every ball, u = 0, a = g = 9.8 m/s2
∴ 4th ball move for 2 sec, 5th ball 1 sec and 3rd ball 3 sec when 6th ball is being dropped. For 3rd ball 
t = 3 sec

S3 = ut + ½ at2 0 + ½ (9.8) 32 = 4.9 m below the top.

For 4th ball, t = 2 sec
S2 = 0 + 1/2 gt2 = 1/2 (9.8)22 = 19.6 m below the top (u = 0)
For 5th ball, t = 1 sec
S3 = ut + 1/2 at2 = 0 + 1/2 (9.8)t2 = 4.98 m below the top.

						
5 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 110 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details