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A person sitting on the top of a tall building is dropping balls at regular intervals of one second. Find the positions of the 3rd. 4th and 5th ball when the 6th ball is being dropped.

Shane Macguire , 10 Years ago
Grade upto college level
anser 1 Answers
Deepak Patra

Last Activity: 10 Years ago

Sol. For every ball, u = 0, a = g = 9.8 m/s2 ∴ 4th ball move for 2 sec, 5th ball 1 sec and 3rd ball 3 sec when 6th ball is being dropped. For 3rd ball t = 3 sec S3 = ut + ½ at2 0 + ½ (9.8) 32 = 4.9 m below the top. For 4th ball, t = 2 sec S2 = 0 + 1/2 gt2 = 1/2 (9.8)22 = 19.6 m below the top (u = 0) For 5th ball, t = 1 sec S3 = ut + 1/2 at2 = 0 + 1/2 (9.8)t2 = 4.98 m below the top.

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