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`        A person sitting on the tall building is dropping balls at regular intervals of one second. Find the position of the 3,4,5th ball when the 6th ball is being dropped`
2 years ago

763 Points
```							Dear Swati,The position of 3rd 4th and 5th ball will be equal to the distance covered by ball in 1 , 2 and  3 second.So distance covered in 1st second = 0.t+1/2.a.t2=1/2.10.1=5mDistance covered in 2 second =0.t+1/2.a.t2=1/2.10.2.2=20mDistance covered in 3 second =0.t+1/2.a.t2=1/2.10.3.3=45mHence distance covered by 3rd,4th and 5th ball is 5m , 20m and 45m. REGARDSAdarsh
```
2 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions