Falling Behind in Studies? Join Our Performance Improvement Batch. Enroll For Free
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
A person on a moving truck with velocity 14.7 m/s on horizontal road throws a ball in such way that it return to the truck after moving 58.8m find the speed and angle of projection as seen from the road
Velocity=14.7 m/s Time taken by the truck to cover 58.8=t=S/v=58.8/14.7 =4secSince ball returns back to truck its angle of projection is vertically upwards with respect to truck.u=speed of projection.t=4sh=0h=4u-1/2 x 9.8x160=4u-78.44u=78.4u=78.4/4=19.6 m/sb) As seen from the road the speed of ball will be resultant of 2 speeds verticalspeed =u=19.6 m/sHorizontal speed given by truck=14.7m/s⇒√u²+v²=√19.6²+14.7²=24.5 m/sThus angle seen from road:Tan⁻¹[19.6/14.7] =Tan⁻¹1.33=Tan⁻¹[4/3]=53°with horizontal.
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -