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Grade: 11

                        

A person on a moving truck with velocity 14.7 m/s on horizontal road throws a ball in such way that it return to the truck after moving 58.8m find the speed and angle of projection as seen from the road

2 years ago

Answers : (1)

Arun
24742 Points
							
Velocity=14.7 m/s 
Time taken by the truck to cover 58.8=t=S/v=58.8/14.7 =4sec
Since ball returns back to truck its angle of projection is vertically upwards with respect to truck.
u=speed of projection.
t=4s
h=0
h=4u-1/2 x 9.8x16
0=4u-78.4
4u=78.4
u=78.4/4=19.6 m/s


b) As seen from the road the speed of 
  ball will be resultant of 2 speeds vertical
speed =u=19.6 m/s
Horizontal speed given by truck=14.7m/s
⇒√u²+v²=√19.6²+14.7²=24.5 m/s
Thus angle seen from road:
Tan⁻¹[19.6/14.7] 
=Tan⁻¹1.33
=Tan⁻¹[4/3]
=53°with horizontal.
2 years ago
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