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`        A person desires to reach a point 3.42km from her present location and in a direction that is 35° north of east however she must travel along the street that go either north south or east west what is the minimum distance she could travel to reach on destination`
6 months ago

Arun
20404 Points
```							The vector with initial point at her present position and terminal point at her desired position is  v = ||v||( cosΘ i + sinΘ j ) = 3.42 cos(35°) i + 3.42 sin(35°) j. The minimum distance traveled with the given restrictions is along the legs 3.42 cos(35°) in the east-west direction and 3.42 sin(35°) in the north-south. It doesn't matter which she does first. No other path is minimum because any other path would require over shooting her target and doubling back---not smart if you want the shortest route! So the distance is  3.42 cos(35°) + 3.42 sin(35°) ≈ 4.74 km
```
6 months ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions