MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 12th pass
        
A person desires to reach a point 3.42km from her present location and in a direction that is 35° north of east however she must travel along the street that go either north south or east west what is the minimum distance she could travel to reach on destination
one month ago

Answers : (1)

Arun
15841 Points
							
The vector with initial point at her present position and terminal point at her desired position is  

v = ||v||( cosΘ i + sinΘ j ) = 3.42 cos(35°) i + 3.42 sin(35°) j. 

The minimum distance traveled with the given restrictions is along the legs 3.42 cos(35°) in the east-west direction and 3.42 sin(35°) in the north-south. It doesn't matter which she does first. No other path is minimum because any other path would require over shooting her target and doubling back---not smart if you want the shortest route! 

So the distance is  

3.42 cos(35°) + 3.42 sin(35°) ≈ 4.74 km 
 
one month ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

Get Extra Rs. 276 off

COUPON CODE: SELF10


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 110 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Get Extra Rs. 297 off

COUPON CODE: SELF10

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details