Jitender Pal
Last Activity: 11 Years ago
Sol. . T = 2sec.
T = 2π √(l/g)
⇒ 2 = 2π √(l/10) ⇒ l/10 = 1/π^2 ⇒ l = 1cm (∴ π^2 ≈ 10)
33. From the eqation,
θ = π sin [π sec-1 t]
∴ ω = π sec-1 (comparing with the equation of SHM)
⇒ 2π/T = π ⇒ T = 2 sec.
We know that T = 2π √(l/g) ⇒ 2 = 2 √(l/g) ⇒ 1 = √(l/g) ⇒ l = 1m.
∴ Length of the pendulum is 1m.