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Grade: upto college level
        A pendulum clock giving correct time at a place where g = 9.800 ms-2 is taken to another place where it loses 24 seconds during 24 hours. Find the value of g at this new place.
5 years ago

Answers : (1)

Navjyot Kalra
askIITians Faculty
654 Points
							Sol. . For the pendulum, T_1/T_2  = √(g_2/g_1 )
Given that, T1 = 2sec, g1 = 9.8m/s2
T2 = (24 × 3600)/(((24 × 3600 -  24)/2) ) = 2 × 3600/3599
Now, g^2/g_1  = (T_1/T_2 )^2
∴ g2 = (9.8) (3599/3600)^2 = 9.795m/s2

						
5 years ago
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