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A passenger reaches the platform and finds that the second least boggy of the train is passing him. The second last boggy takes 3 s to pass the passenger, and the last boggy takes 2 s to pass him. Find the time by which the passenger late for departure of the train? Assume that the train accelerates at constant rate and all the boggies are of equal length

```
3 years ago

Arun
25768 Points
```							Let say Velocity of Train = V  at the time of 2nd last boggie start crossing ManDistance Covered in 3 secS = V3  + (1/2)a3²S = 3V + 4.5aDistance Covered in 2 secsDistance Covered in 5 sec - Distance Covered in 3 secS = 5V + 12.5a - 3V - 4.5a  = 2V +  8aas length of boggies are equal3V + 4.5a = 2V +  8a=> V = 3.5aV = 0 + at=> 3.5a = 0 + at=> t = 3.5passenger is 3.5 sec late for the departure of the train​ Hope it helps
```
7 months ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions