badge image

Enroll For Free Now & Improve Your Performance.

×
User Icon
User Icon
User Icon
User Icon
User Icon

Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 11

                        

A passenger reaches the platform and finds that the second least boggy of the train is passing him. The second last boggy takes 3 s to pass the passenger, and the last boggy takes 2 s to pass him. Find the time by which the passenger late for departure of the train? Assume that the train accelerates at constant rate and all the boggies are of equal length

3 years ago

Answers : (1)

Arun
24742 Points
							
Let say Velocity of Train = V  at the time of 2nd last boggie start crossing Man
Distance Covered in 3 sec
S = V3  + (1/2)a3²
S = 3V + 4.5a
Distance Covered in 2 secs
Distance Covered in 5 sec - Distance Covered in 3 sec
S = 5V + 12.5a - 3V - 4.5a  = 2V +  8a
as length of boggies are equal
3V + 4.5a = 2V +  8a
=> V = 3.5a
V = 0 + at
=> 3.5a = 0 + at
=> t = 3.5
passenger is 3.5 sec late for the departure of the train​
 
Hope it helps
5 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 110 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details