Falling Behind in Studies? Join Our Performance Improvement Batch. Enroll For Free
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
A particle with mass m = 0 (a neutrino, possibly) carries momentum. How can this be in view of Eq. 6-1, in which we see that the momentum is directly proportional to the mass?
The momentum of a particle (p) is equal to the mass of the particle (m) times the velocity of particle (v). So, p = mv …… (1)But according to de Broglie hypothesis, the momentum of a particle (p) is equal to the Planck’s constant (h) divided by wavelength of the particle (λ).So, p = h/ λ …… (2)Multiplying a constant c (velocity of light) in numerator and denominator of equation (1), we get,p = h/ λ = hc/ λc= hf/c (Since, c/λ = f (frequency))= E/c (Since, E (energy) = hf) …… (3)From equation (3), quantum mechanically the momentum of a neutrino having zero mass (m = 0) does not depend upon the mass of the particle, it depends on the energy of the particle.Thus a particle having zero mass still has a momentum.
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -