Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

A particle with mass m = 0 (a neutrino, possibly) carries momentum. How can this be in view of Eq. 6-1, in which we see that the momentum is directly proportional to the mass?

A particle with mass m = 0 (a neutrino, possibly) carries momentum. How can this be in view of Eq. 6-1, in which we see that the momentum is directly proportional to the mass?

Grade:upto college level

1 Answers

Deepak Patra
askIITians Faculty 471 Points
6 years ago
The momentum of a particle (p) is equal to the mass of the particle (m) times the velocity of particle (v).
So, p = mv …… (1)
But according to de Broglie hypothesis, the momentum of a particle (p) is equal to the Planck’s constant (h) divided by wavelength of the particle (λ).
So, p = h/ λ …… (2)
Multiplying a constant c (velocity of light) in numerator and denominator of equation (1), we get,
p = h/ λ
= hc/ λc
= hf/c (Since, c/λ = f (frequency))
= E/c (Since, E (energy) = hf) …… (3)
From equation (3), quantum mechanically the momentum of a neutrino having zero mass (m = 0) does not depend upon the mass of the particle, it depends on the energy of the particle.
Thus a particle having zero mass still has a momentum.

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free