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A particle starts with initial speed u and retardation a to come to rest in time t . The time taken to cover first half of the total path travelled is . Please explain properly

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5 years ago

Nicho priyatham
625 Points
```							while solving 1 diminsion  problems in kinamitcs u have to remember 3 important equations s=ut+(1/2)at2=vt-(1/2)at2 …......(1)v=u+at..........(2)v2-u2=2as........(3)now coming to problemu=u v=0a=-a(retardation)	by apply second equation above we get            0=u-at so u=at............(3)	now apply first equation  and substuting eq 3         s=(1/2)at2 =(1/2)ut …........(4)	now say partical takes T seconds to cover s/2 applying eq 1 again and sudstuting eq 4                      s/2=uT-(1/2)aT2                               1/4ut=uT-(1/2)(u/t)T2                                solving the above equation we get the quaratic                                 2T2 -4tT+t2=0  solving the above equation we get T=(1-(1/(root2))t or (1+(1/(root2))t (reject as greater than t)so T=(1-(1/(root2))t PLEASE APROOVE
```
5 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions