A particle starts moving at t=0 from origin along positive X axis. Its speed depends on the distance traveled x as v=k√x . If v=dx/dt and a=dv/dt, then find x,v and a in terms of time. The answer is k(square) t(squ)/4, k(squ)t/2, k(squ)/2 respectively. pls explain

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Khimraj · Answer

v = k √x dx/dt = k√x dx/√x = kdt integerating both side 2√x = kt x = k 2 t 2 /4 v = dx/dt = k 2 t/2 a = dv/dt = k 2 /2 Hope it clears.............................................

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A particle starts moving at t=0 from origin along positive X axis. Its speed depends on the distance traveled x as v=k√x . If v=dx/dt and a=dv/dt, then find x,v and a in terms of time. The answer is k(square) t(squ)/4, k(squ)t/2, k(squ)/2 respectively. pls explain

A particle starts moving at t=0 from origin along positive X axis. Its speed depends on the distance traveled x as v=k√x . If v=dx/dt and a=dv/dt, then find x,v and a in terms of time.
The answer is k(square) t(squ)/4, k(squ)t/2, k(squ)/2 respectively.
pls explain

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A particle starts moving at t=0 from origin along positive X axis. Its speed depends on the distance traveled x as v=k√x . If v=dx/dt and a=dv/dt, then find x,v and a in terms of time. The answer is k(square) t(squ)/4, k(squ)t/2, k(squ)/2 respectively. pls explain

A particle starts moving at t=0 from origin along positive X axis. Its speed depends on the distance traveled x as v=k√x . If v=dx/dt and a=dv/dt, then find x,v and a in terms of time.The answer is k(square) t(squ)/4, k(squ)t/2, k(squ)/2 respectively.pls explain

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A particle starts moving at t=0 from origin along positive X axis. Its speed depends on the distance traveled x as v=k√x . If v=dx/dt and a=dv/dt, then find x,v and a in terms of time.
The answer is k(square) t(squ)/4, k(squ)t/2, k(squ)/2 respectively.
pls explain