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A particle starts moving at t=0 from origin along positive X axis. Its speed depends on the distance traveled x as v=k√x . If v=dx/dt and a=dv/dt, then find x,v and a in terms of time.The answer is k(square) t(squ)/4, k(squ)t/2, k(squ)/2 respectively.pls explain
v = k√xdx/dt = k√xdx/√x = kdtintegerating both side2√x = ktx = k2t2/4v = dx/dt = k2t/2a = dv/dt = k2/2Hope it clears.............................................
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