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`        A particle starts from rest with uniform acceleration a. Its velocity after n seconds is v. the displacement of the particle in the last two seconds is.....`
4 years ago

erra akhil
208 Points
```							Dear Pranjal,v = u + a t -----eqn.1v-final velocityu-initial velocitya-accelerationt-time takenlet the velocity of the particle be v` just two seconds before which means t=(n-2) secondsSince initial velocity=0.on applying eq.1,v`=0+a(n-2)Now,S = u t + (1/2) a t2So the displacement in the last two seconds ishere the velocity before two seconds as found above is {(n-2)a} which becomes initial velocity for last 2 seconds and time is 2 seconds because we want displacement for last 2 secondsS = {a (n-2) } 2 + (½) a (22)S = 2 a (n-2) + 2aS= 2an-2aS= 2a(n-1) for last two seconds.
```
4 years ago
erra akhil
208 Points
```							Approve if my answer helped you
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4 years ago
Srinivas
13 Points
```							A particle starts from rest moving with uniform acceleration and covers 26m in 7th Second. Find it's displacement 9th second
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one year ago
Raushan kumar
16 Points
```							A particle is moving with constant acceleration from A to B in a straight line AB .If u and v are the velocities at A and B respectively, then it's velocity at the midpoint c will be
```
one year ago
Raushan kumar
16 Points
```							A particle is moving with constant acceleration from A to B in a straight line AB. If u and v are the velocities at A and B respectively , then it's velocity at the midpoint c will be
```
one year ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions