×

#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
```
a particle starts from rest with accelaration a and after each second accelaration abruptly becomes one third of previous one then the final velocity of particle is what
a particle starts from rest with accelaration a and after each second accelaration abruptly becomes one third of previous one then the final velocity of particle is what

```
3 years ago

Rae
25 Points
```							According to the given condition; da/dt = a/3 – a         = -(2a/3)da/dt = -(2dv/3dt)   da=-(2dv/3)intergrate on both the sides with limits for aacceleration as a to 0 and for velocity as 0 to v; You will get; 3(0-a)=-2(v-0)  -3a=-2v v=3a/2 Thats it!
```
3 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Mechanics

View all Questions »

### Course Features

• 101 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions