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a particle starts from rest with accelaration a and after each second accelaration abruptly becomes one third of previous one then the final velocity of particle is what
According to the given condition; da/dt = a/3 – a = -(2a/3)da/dt = -(2dv/3dt) da=-(2dv/3)intergrate on both the sides with limits for aacceleration as a to 0 and for velocity as 0 to v; You will get; 3(0-a)=-2(v-0) -3a=-2v v=3a/2 Thats it!
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